A log 10 m long is cut at 1-meter intervals and its cross- sectional areas $ A $ (at a distance x from the end of the log) are listed in the table. Use the Midpoint Rule with $ n = 5 $ to estimate the volume of the log.

$V=5.8 m^{3}$

Applications of Integration

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Numerade Educator

Oregon State University

University of Nottingham

Boston College

in order to use the midpoint rule. The first thing we have to remember is that are changing Accer. Delta Axe is gonna be too. Which means now we're looking at the volume. We have two times a of one plus a two. Plus I have three plus. I have four plus a five to give us five point a meters. Cute.