Given cohesion ($c$) = 24 kPa, angle of internal friction ($\phi$) = 25°, and soil rigidity index = 50.
$c' = c \times (1 + 0.2 \times \sqrt{I})$
$c' = 24 \times (1 + 0.2 \times \sqrt{50})$
$c' = 24 \times (1 + 0.2 \times 7.07)$
$c' = 24 \times (1 + 1.414)$
$c' =
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