00:01
Hello friends, as shown in the figure there is a long ladder of length l.
00:07
So av is the ladder having the length l and mass m.
00:18
Its central temporal moment of inertia is given i and leaning against a house at angle theta knot.
00:36
So at this angle it is initially at rest so omega 1 is 0.
00:41
We have to find angular velocity for theta to v, theta 2.
00:51
Let us see here.
00:54
We will discuss the kinematics of it.
00:57
B will move vertically downward.
01:03
A will move towards left with velocity b .a.
01:09
If we draw the perpendicular from here and here, then we will get instantaneous center.
01:16
So c will be the instantaneous center of rotation.
01:30
This is center of mass having the velocity vg.
01:44
From the geometry you may say the length of ga or gv to be half of the length of the rod, that is ly2.
01:56
The velocity of center of mass is given by omega ly2...