Question
A long solenoid has 1000 turns and is $0.250 \mathrm{~m}$ long. If the wire carries a current of $2.50 \mathrm{~A}$, what is the strength of the magnetic field at its center?
Step 1
This is given by the total number of turns divided by the length of the solenoid. In this case, we have 1000 turns and a length of 0.250 m. So, we have: \[ n = \frac{1000}{0.250} \] Show more…
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