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Problem 5 Easy Difficulty

A long, straight wire lies in the plane of a circular coil with a radius of 0.010 m. The wire carries a current of 2.0 A and is placed along a diameter of the coil. (a) What is the net flux through the coil? (b) If the wire passes through the center of the coil and is perpendicular to the plane of the coil, what is the net flux through the coil ?

Answer

a. zero
b. \phi=B A \cos \theta = 0

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Video Transcript

are. So in this first case here, which is case, eh? You have your circular loop of wire, your particular coil and the wire that's going through along the plane of bucks. That's that's on the plane off the coil. So what's happening is that, um uh and this is the face on view, by the way, you're seeing this face on some. What's happening is that, um so this is a field line. Be right, every few lines. So we know that Ah, magnetic flux will be be a Times co sign data. So the angle between the magnetic field of ah plane of the loop is it's 90 degrees. So that's s so it will be be a here. But the problem is that every time the the net flux, um, won't necessarily be amount zero value because what's happening here is that every time every field line that comes up through to this area into an area and one side of the wire, let me draw this again, um, for better for clarity. So from one side of the wire, dis pretended, this is this is along the diameter, off the off the, um, coil off the loop. Every feline that's going to the center from on one side of the wire goes back down. Um, goes back down through area on the other side of the wire. Okay, so the net flocks. The net will be zero due to the cemetery property and part b, um, has on put B. We just used the fact that Faison be eyes equal to be a co side data and so co sign. Ah, 90. Because of this angle, here is 97 data zero. In this case, sure, if they does 90 and co side 90 is zero. So this will be zero as well, hence the net flux will be zero.

New Mexico State University
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Elyse G.

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