00:01
We're told that we have a long thin solenoid with 900 turns per meter, so that's in.
00:05
Of course, the permeativity here, mu not is 1 .25 times 10 to the minus 6 nune per ampiers.
00:11
And we increased the solenoid at a uniform rate.
00:14
D -i -d -t then is 36 ampers per second.
00:18
And the radius, which i call r, is 0 .025 meters.
00:24
Okay, then to find the electric field at a point zero to five meters.
00:30
Point near the center.
00:31
First, we're going to use e .d .s.
00:38
Is equal to minus the integral of dbdt .t.
00:49
Okay, well, the magnetic field, b is equal to mu not times the number of turns times the current i.
01:03
Therefore d b d t is equal to mu not times the number of turns times di d t and we know all of those values so then going back up to the integral the left side of the integral is the electric field times two pi r where the right side is equal to mu not times the number of turns times d i d t times pi r squared in general for the first case if we're trying to solve for the center so we'll start another page here so therefore the electric field is equal to mu not times the number of turns times d i d t multiplied by r the pies cancel out divided by two so plugging all those values of the expression we find that near the center the electric field is equal to 5 .09 times 10 to the minus 4, and then the units here would be newton's per coolum.
02:47
So we can go ahead and box that in...