Question
A long wire having a semi-circular loop of radius $r$ carries a current $i$ as shown in figure. The magnetic induction at the centre $c$ due to the entire wire is(a) $\frac{3 \mu_{o} i}{4 r}$(b) $\frac{\mu_{o} i}{2 r}$(c) $\frac{\mu_{a} i}{4 r}$(d) $\frac{\mu_{a} i}{8 r}$
Step 1
The magnetic field at the center of a circular loop carrying current is given by $B = \frac{\mu_{0}i}{2r}$. But since we only have a semi-circular loop, the magnetic field will be half of this, i.e., $B = \frac{\mu_{0}i}{4r}$. Show more…
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Magnetic Effect of Current
Round 2
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