00:01
Hi guys, in this problem we are given some information for the sample sizes for two samples and their sample means and their variances.
00:11
Okay, so the null hypothesis is that new one equals mu two and the alternative hypothesis is new one does not equal mu two.
00:20
Okay, so to find the test statistics, we need to find the pool estimator first.
00:25
So we need to find sp squared.
00:29
Okay.
00:30
Which is okay um n1 minus 1 times s 1 squared plus n2 minus 1 times s 2 squared over n1 minus n 2 minus okay so this is 0 .3767 okay and then we find sp, it's just the square root of 0 .37, 6 ,7, okay? so it's 0 .617.
01:17
Okay.
01:19
Now let's find statistics.
01:21
So t node is x1 -power minus x2 power minus 0 over sp times the square root of 1 over n1 plus 1 over n2 okay so this is um 0 .05 over 0 .274 okay so it's 0 .20 okay so now let's find the degrees of freedom so it's 15 minus 17 which is n1 minus and plus n2 minus 2 minus 2 minus 2 minus 2 so it's 30 okay so for the t table at level of significance 0 .05 we have t of alpha over node over 2 and degrees of freedom it's alpha of 0 .025 and 30 okay so it's 2 .0 4 and since we know that t node is 2 .0 .23 which is less than the t critical value.
02:33
So we fail to reject the null hypothesis and conclude that there is no significant difference between the two means...