Question
A magnet of length $0.1 \mathrm{~m}$ and pole strength $10^{-4} \mathrm{~A} \mathrm{~m} .$ is kept in a magnetic field of 30 tesla at an angle of 300 . The Torque acting on it is $\times 10^{-4}$ Joule.(a) $7.5$(b) 3(c) $1.5$(d) 6
Step 1
We know that the torque acting on a magnet in a magnetic field is given by the formula: τ = m * B * sinθ, where m is the magnetic moment, B is the magnetic field, and θ is the angle between the magnetic moment and the magnetic field. Show more…
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A bar magnet of length 0.2 m and pole strength 5 A.m. should be kept in a uniform magnetic field of induction 15 tesla at angle ..... radians to the field so that the torque experienced by it will be 7.5N-m ?
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