00:03
We have given information for part a.
00:09
We have to write the equation between iron, iron tree oxide and hcl.
00:51
So the equation is ap2 -03 iron oxide plus hcl.
00:59
Iron chloride plus h2o water.
01:14
Since we have two iron atoms and reactant site and only one on product side we will place two in front of fecl 3 so the equation become vap2 o3 plus hcl and we will place to in front of fecl fcl 3 plus h2 .0.
02:03
Now we have 6 chlorine atoms on product side.
02:08
6 chlorine atoms on product side 2 into 3 is 6 and 1 on reactant side.
02:18
1 chlorine atom is on reactant side.
02:21
So we will place 6 in front of hcl in reactant site.
02:26
So the equation become f .e .203 plus 6 hcl to fecl3 plus h2o.
02:42
Now there are 6 hydrogen, 6 hydrogen atoms on reactant side and 2 on the product side.
02:53
Hence we will place 3 in front of h2o and get the balance equation.
02:59
And here we put 6 and 3 in front of h2o and it becomes 6 3 into 2 is 6 and the equation become balance.
03:13
So we have the equation f .e2 .03 plus 6 hcl to fecl 3 plus 3 h2o.
03:34
So the final result will be f .e .203 plus 6hcl to fecl3 plus 3h2o.
03:57
This is balance equation.
04:12
And given information for part b, fe2o3 plus 6hcl.
04:24
To fecl 3 plus 3 is 2o so the number of moles of moles of f .e .203 is n f .e2 -03 is equal to 1 .22 the mass of hcl is mass of hcl is equal to to 8 .9 .2 gram.
05:30
We have to find the mass of fecl free that will be produced.
06:01
So first we will find the number of moles of hl.
06:21
The hcl molar masses mass is mass is molar mass of hcl is equal to molar mass of hydrogen plus molar mass of chlorine is equal to molar mass of hydrogen is 1 .008 gram per mole plus molar mass of chlorine is 35 .453 gram per mole is equal to molar mass of mass of hcl is 36 .461 gram per mole.
07:17
The number of moles of hcl is number of moles of hcl is equal to mass of hcl divided by molar mass of hcl is equal to mass of hcl...