00:01
So for a and b, the weight of the child and the magnitude with which the father is pushing the child, we can simply use, for a and b, we can simply use newton second law.
00:13
So the sum of forces in the y direction would equal zero.
00:16
And this would give us the weight of the child equaling the tension times cosine of theta.
00:22
And this is equaling 270 newtons for the weight of the child.
00:26
This would be your answer for part a.
00:28
For part b, we're going to say that the sum of forces in the x direction would be, rather would give us p, the pushing force of the father, t, sine of theta.
00:41
This is equaling 72 newtons.
00:43
This would be our answer for part b, the pushing force of the father.
00:48
We know that here the tension and the rope is equal in 280 newtons, and theta is equal in 15 degrees...