Question
A man and woman are both heterozygous for the recessive allele that causes cystic fibrosis. What is the probability that their first two offspring will have the disorder?a. 1b. $1 / 4$c. $1 / 16$d. $1 / 32$e. 0
Step 1
This means that each parent has one dominant allele and one recessive allele. The dominant allele is usually represented by a capital letter (A) and the recessive allele by a lower case letter (a). So, each parent's genotype can be represented as Aa. Show more…
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Cystic fibrosis disease is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers have a child. What is the probability of that child to have cystic fibrosis?! In other words: In a cross between Cc x Cc (parents are heterozygotes) what is the probability of the offspring to be cc ?! a. 2/4 b. 1/2 c. 1/4 d. 3/4
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