Question

A man can row with the stream at $7 \mathrm{~km} / \mathrm{hr}$ and against the stream at $3 \mathrm{~km} / \mathrm{hr}$. His speed in still water is: (a) $6.5 \mathrm{~km} / \mathrm{hr}$ (b) $7 \mathrm{~km} / \mathrm{hr}$ (c) $5 \mathrm{~km} / \mathrm{hr}$ (d) None of these

   A man can row with the stream at $7 \mathrm{~km} / \mathrm{hr}$ and against the stream at $3 \mathrm{~km} / \mathrm{hr}$. His speed in still water is:
(a) $6.5 \mathrm{~km} / \mathrm{hr}$
(b) $7 \mathrm{~km} / \mathrm{hr}$
(c) $5 \mathrm{~km} / \mathrm{hr}$
(d) None of these
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The Pearson Guide to Objective Arithmetic for Competitive Examinations
The Pearson Guide to Objective Arithmetic for Competitive Examinations
Dinesh Khattar 2nd Edition
Chapter 16, Problem 4 ↓

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Step 1

Step 2: According to the problem, the speed of the man with the stream (downstream) is given by the equation: \[ x + y = 7 \quad \text{(1)} \] This represents the speed of the man rowing with the current. Step 3: The speed of the man against the stream  Show more…

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A man can row with the stream at $7 \mathrm{~km} / \mathrm{hr}$ and against the stream at $3 \mathrm{~km} / \mathrm{hr}$. His speed in still water is: (a) $6.5 \mathrm{~km} / \mathrm{hr}$ (b) $7 \mathrm{~km} / \mathrm{hr}$ (c) $5 \mathrm{~km} / \mathrm{hr}$ (d) None of these
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