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A man consumes 3000 kcal of food in one day, converting most of it to maintain body temperature. If he loses half this energy by evaporating water (through breathing and sweating), how many kilograms of water evaporate?
Physics 101 Mechanics
Chapter 14
Heat and Heat Transfer Methods
Thermal Properties of Matter
Rutgers, The State University of New Jersey
University of Michigan - Ann Arbor
Simon Fraser University
Hope College
Lectures
02:20
A solid, liquid, or gas is…
06:13
Matter is a state of aggre…
02:19
A man consumes 3000 kcal o…
02:01
During a strenuous workout…
01:41
The latent heat of vaporiz…
01:59
A person ate 0.50 pound of…
01:04
It has been determined tha…
00:51
01:19
A man ate 0.50 pound of ch…
08:38
A 50 -kg person consumes a…
03:03
(a) How many kilograms of …
04:10
Metabolic activity in the …
02:40
A 60.0 -kg runner expends …
00:57
A marathon runner has an a…
02:05
How many calories are need…
01:47
Evaporation of sweat is th…
06:23
In exercising, a weight li…
03:34
02:43
(I) During exercise, a per…
03:15
The fuel value of hamburge…
01:18
02:26
In a study of healthy youn…
in this problem. We're told that a human man uses 3000 kilocalories per day and we want to know how much water in kilograms would it take evaporating to make up half of that energy. So we're gonna use this equation. Q equals massive water times the latent heat of vaporization, remembering that we're at 37 degrees Celsius body temperature. So if you look that up, that is 580 killer cal per kilogram, which is in the footnotes on the table in your textbook, because the latent heat can change depending on the temperature of the material. So our heat in this case, it's rearranges equation and w sure what we're looking for equals Q over LV. In this case, the queue is half specifically were asked for half of the energy 3000 kilocalories divided by the 5 80 killer cows per kilogram Thes cancel and you are left with 2.59 kilograms
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