A man is standing on a spring balance. Reading of spring balance is 60 kg f. If man jumps outsi

step 1 Hi, welcome to the solution of problem number 376. The man is standing on a spring balance. So,

A man is standing on a spring balance. Reading of spring...

A man is standing on a spring balance. Reading of spring balance is $60 \mathrm{~kg} \mathrm{f}$. If man jumps outside balance, then reading of spring balance
(A) First increase than decreases to zero
(B) Decreases
(C) Increases
(D) Remains same

Key Concepts

Newton's Second Law

Newton's Second Law (F = ma) explains how the net force acting on an object produces acceleration. When an object accelerates, such as when jumping off a spring balance, the forces acting on the object and the reactive forces from the measuring device change, resulting in a different normal force reading than when the object is stationary.

Free Fall

In free fall, an object accelerates downward at the acceleration due to gravity, effectively making the normal force between the object and the support (like a spring balance) approach zero. This reduction in support force is key in understanding changes in measured weight when the object is momentarily not in firm contact with the balance.

Spring Balance Mechanics

A spring balance measures the force exerted on it based on the extension of a spring, which is directly proportional to the force applied (following Hooke’s law). The reading is determined by the normal force that the object imparts on the balance rather than its actual mass, especially when the object is subject to acceleration.

Apparent Weight

The apparent weight is the normal force experienced by an object and is what a spring balance reads. It can differ from the actual gravitational weight if the object is accelerating. For example, during free fall or upward motion, the balance records less force than what would be expected under static conditions, leading to a lower reading.

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