A man reaches his destination which is 16 km away, 9 min late, if he travels at 8 kmph. What sh

step 1 Hi, here in this given problem, distance of the destination for the man, that is S is equal to 1

A man reaches his destination which is 16 km away, 9 min...

A man reaches his destination which is $16 \mathrm{~km}$ away, 9 min late, if he travels at $8 \mathrm{kmph}$. What should his speed be if he wishes to reach 15 minutes ahead of the right time? (A) $10 \mathrm{kmph}$ (B) $3 \mathrm{~m} / \mathrm{sec}$ (C) $20 / 9 \mathrm{~m} / \mathrm{sec}$ (D) $12 \mathrm{kmph}$

A man reaches his destination which is $16 \mathrm{~km}$ away, 9 min late, if he travels at $8 \mathrm{kmph}$. What should his speed be if he wishes to reach 15 minutes ahead of the right time?
(A) $10 \mathrm{kmph}$
(B) $3 \mathrm{~m} / \mathrm{sec}$
(C) $20 / 9 \mathrm{~m} / \mathrm{sec}$
(D) $12 \mathrm{kmph}$

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Key Concepts

Speed-Distance-Time Relationship

This fundamental concept in kinematics establishes that time is equal to distance divided by speed, which allows one to solve for any of these three variables when the other two are known. It forms the basis for solving motion problems in both theoretical and practical contexts.

Unit Conversion between Minutes and Hours

Accurate problem-solving in motion requires consistent units, especially when time is given in minutes and speed in kilometers per hour. Converting minutes to hours (or vice versa) is essential for applying the speed-distance-time formula correctly.

Time Adjustment for Arrival (Lateness and Advancement)

This concept involves modifying the planned travel time based on delays or early arrivals. Understanding how to adjust the actual travel time to meet specific scheduling requirements is crucial for planning and optimizing travel speeds.

Algebraic Equation Setup and Solving

Establishing equations that encapsulate the given information and relationships between variables is key in mathematics. By representing the problem parameters algebraically, one can systematically solve for unknown quantities using basic algebraic techniques.

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