Question
A man squatting on the ground gets straight up and stands. The force of reaction of ground on the man during the process is(A) Constant and equal to $\mathrm{mg}$ in magnitude.(B) Constant is greater than $\mathrm{mg}$ in magnitude.(C) Variable but always greater than $\mathrm{mg}$.(D) At first greater than $\mathrm{mg}$ and later becomes equal to $\mathrm{mg}$.
Step 1
In addition to this, there is also a frictional force acting on him. Therefore, the total reaction force of the ground on the man is the sum of these two forces, which is greater than $\mathrm{mg}$. Show more…
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