Problem

A baseball diamond is a square with side $ 90 ft.…

07:43

Problem 19 Medium Difficulty

A man stars walking north at $ 4 ft/s $ from a point $ P. $ Five minutes later a woman starts walking south at $ 5 ft/s $ from a point $ 500 ft $ due east $ P. $ At what rate are the people moving apart $ 15 min $ after the woman starts walking?

Name: a man stars walking north at 4 fts from a point p five minutes later a woman starts walking south at
Uploaded: 2021-04-07
Duration: 8 min 37 s
Channel: Numerade
Description: A man stars walking north at $ 4 ft/s $ from a point $ P. $ Five minutes later a woman starts walking south at $ 5 ft/s $ from a point $ 500 ft $ due east $ P. $ At what rate are the people moving apart $ 15 min $ after the woman starts walking?

Answer

$$8.99 \mathrm{ft} / \mathrm{s}$$

Grace H.

Catherine R.

Missouri State University

Anna Marie V.

Campbell University

Samuel H.

University of Nottingham

Watch More Solved Questions in Chapter 3

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

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Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

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Problem 32

Problem 33

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Problem 35

Problem 36

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Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

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Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Video Transcript

take. We're told that a man starts walking north at four ft per second from a point p five minutes later, a woman starts walking south at five ft per second from a 50.500 ft due east of P. And were asked, At what rate are the people moving apart 15 minutes after the woman starts walking? Yeah, To understand this problem, let's draw a diagram. Zeffirelli. So we're just gonna put P r points at the origin? Yeah. Certain point. Move. Yes. Mhm. In the real stuff, I just was, like, 18 hours. But let me tell you some. Yes? Watch. Yes. Don't know how. Romeo. Yeah, right. Mhm. Okay, Now the man heads north ends up around here somewhere. The woman and head south ends up around here somewhere. The distance between horizontal distance from P to the woman is always 500 feet, right? All right, long hair just really should. And so there's a few different unknowns here. So we have this unknown this length here, which I'll call a this length here, which I'll call B and this last length here, which I'll call s sure make sure, actually, let's flip those. I'll call this a and this be It's Yeah, we should now from our diagram. Yeah. Mhm. You know, the man m has been walking for a total of oh, five miles? Yes. What b I did. I took, like because you needed to. Sorry, The man has been walking for a total of five minutes. Plus, then the 15 minutes after the woman starts for a total of 20 minutes. And so his distance from the point p a is equal to the rate he walks at, which is four ft per second, times the time in 20 minutes times the 60 seconds per minute. Yeah, which is equal to 4800. And the units is in feet course, A short 100. Because the history the woman w has been walking for a total of 15 minutes. See? So seriously? Mm, wow. And therefore, the distance be south of P. Yes. Mm hmm. The rate at which one walks five ft per second times the time. 15 minutes times 60 seconds per minute. This is equal to 4500. Right? And this is in feet. Yes. Now a plus B is one leg of the triangle mhm and we're told that d a d t. This is the radio. It's the man is walking, which is five ft per second. And the B D t is the rate at which the woman is walking, which is Yeah, Sorry. DDT was four ft per second and the B D t was five ft per second. It's around your people. Therefore, yes, as the the rate at which a plus B changes with respect to t. This is yeah, medal linearity of the derivative is D A d t plus DBT, which is four plus five, which is nine. And this is again in feet per second. Yeah, yeah. And at the moment in question, distance s between the man and woman. Well, this is the hypotenuse of a right triangle which is square root of a plus B at this time squared, plus the other leg which is 500 squared, which is equal to the square root of 4800 plus length of B which was 4500 squared plus 500 squared. And this is approximately 9313. But you were in the Nazi 0.43116 Yes. And this is in feet. This is a guy that loves me. Okay, well, I'm currently now. We want to find DS DT To do this, we're going to differentiate the Pythagorean theorem, So a plus B squared plus 500 squared equals s squared. And so we have differentiating both sides of respected T two times a plus B times d a d t plus DVD t plus zero is equal to two s times. DS DT mm. Never showed. Yeah, so we have DS DT is equal to a plus b times, and this is the derivative of a plus b t t all over s just like he's not. Yeah, and so plugging in our values. A plus b is 4800 plus 4500 times the derivative A plus B with respect to t. We found this was nine over s, which was approximately 9000 313 points. 43116 Plugging this into a calculator. This is approximately 8.987 Yeah, and the units are in feet per second. Read the entire who does she write for? I mean, once you, if you sign are in be having this conversation

Chris T.

Ohio State University

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