00:02
In this problem, we have a person that is resting between two walls by pushing his hands and feet on wall a and pushing his back on wall b.
00:17
The problem asks us for two things.
00:20
First, to show that the force exerted by the person in each wall is equal in magnitude and what is the normal force exerted by each wall on the person.
00:35
So to solve this problem, we have to apply newton's law of motion.
00:42
First, we will though the diagram of the forces acting on the person's body.
00:57
Shuming, this is the person and this is the wall.
01:05
The forces acting on the person are the normal force exerted by wall b, the normal force exerted by wall a, the weight of the force exerted by wall b, the normal force exerted by wall a, the weight of the the person and the friction force that is opposite the downward pull of the weight, which is both for each wall.
01:54
Now, to prove that the force exerted by person each wall are equal in magnitude, we have to write down the forces acting on the man or the person in the horizontal plane.
02:14
Applying first law of motion, since this person is at rest, then the net force on the horizontal plane acting on its body is equal to zero.
02:30
The forces on this plane are the normal force exerted by wall b, the normal force exerted by wall a.
02:50
This is negative since it's opposite, the normal force exerted by wall b.
02:56
Then equation becomes normal force exerted by wall b is equals to normal force exerted by wall a.
03:07
Thus, this means that normal force exerted by each wall is equal in magnitude.
03:32
But what the problem is asking is the force exerted by the person.
03:38
Now, we will apply third law of motion that states that in every action, there is an equal.
03:44
Wall in opposite reaction...