Question
A manager has available a pool of 8 employees who could be assigned to a project-monitoring task. 4 of the employees are women and 4 are men. 2 of the men are brothers. The manager is to make the assignment at random so that each of the 8 employees is equally likely to be chosen. Let $A$ be the event "chosen employee is a man" and $B$ the event "chosen employee is one of the brothers."a. Find the probability of $A$.b. Find the probability of $B$.c. Find the probability of the intersection of $A$ and $B$.
Step 1
So, the probability of event A, which is the event that the chosen employee is a man, is the number of men divided by the total number of employees. Therefore, the probability of A is $\frac{4}{8}$. Show more…
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Probability
Intersection of Events and the Multiplication Rule
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