00:01
Hello, welcome to this lesson in this list we have a manufacturer detail and that claims that the contents of the bus so weigh on average at least 16 ounces so here the distribution is normal with standard deviation of 0 .4 and we have a sample of 16 boxes that yield a sample mean weight of 15 .84 ounces so we'll test this with a level of significance as 10 % alright, so let's use about six steps to do this.
00:39
So the step one will look at the statistical hypothesis given the null hypothesis, so here we see that the mean weight the population mean weight is at least 16 ounces alright then also have the alternative that would also state that the population mean weight is less than 16 ounces right.
01:24
Let's go to step 2 where would identify the level of significance so we have level of significance and thus alpha which is 0 .1.
01:42
Okay, so we use this level of significance to get the weight degrees of freedom or the sample size minus 1 to find the critical value right the t -critical value, right? let's go to step 3 where we find the test statistic test statistic so here we are looking at the t calculated so in finding the t calculated would actually have the x that is the sample mean minus the population mean divided by the standard deviation all on square root of the sample size okay.
02:34
So here we have fifteen point eight four minus sixteen divided by 0 .4 then divided by square root of sixteen okay, so here we have the t calculated which is equals to 0 .16 divided by 0 .4 times square root of 16.
02:55
So this is supposedly negative 1 .6 let me put it to to the smart places...