Question
A mass $m$ is attached to a spring and displaced from equilibrium. The mass is released, and the system begins to oscillate at frequency $f$ . The mass is replaced with a new mass of 2$m$ and is again displaced by the same amount. The new frequency of oscillation will be(A) $\frac{\sqrt{2}}{2} f$(B) $f$(C) $\sqrt{2} f$(C) $\sqrt{2} f$(D) 2$f$(E) 4$f$
Step 1
Step 1: The frequency of oscillation of a mass-spring system is given by the formula: \[f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}\] where \(k\) is the spring constant, \(m\) is the mass, and \(f\) is the frequency. Show more…
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Oscillations
Round 1
A weightless spring which has a force constant oscillates with frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from it. The frequency of oscillation will now become (a) n (b) 2n (c) n / 2 (d) n(2)^0.5
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