00:01
A mass m with 4 .5 kg is attached to a vertical spring with k equals to 200 newton per meter and is set into a motion.
00:12
Then what is the frequency of the oscillation? b, if the amplitude is 3 .5 centimeter, then what is the value for maximum velocity? for c, how long does it take to move the mass? from y equals to 1 .5 centimeter to y equals to 2 .5 centimeter for d if the mass is oscillating with the maximum speed of 45 meter per second then what will be the amplitude for e if the spring constant is increased by factor two and the maximum kinetic energy is same then by what factor the amplitude will change.
01:05
Frequency is given by 1 by 2 pi root k by m.
01:10
Then substituting here the values, we will get the frequency, which is 1 by 2 pi root of 200 divided by 4 .5 is equal to 1 .06 hertz, which can be approximated to 1 .1 hertz.
01:28
Now for amplitude in meters is 3 .5 into 10 raised to the power minus 2 meter.
01:39
The maximum velocity is given by 2 pi f a cost of 2 pi f t.
01:50
Here the velocity will be maximum when this term, cause of this term will be equals to plus 1.
01:57
Then maximum velocity is equal to 2 pi f into a.
02:01
And the equation y equals to a sign 2 pi f t which can be rewritten as for time is equal to 1 by 2 pi f sign inverse of y by a so maximum velocity is equal to 2 pi into 1 .1 into 3 .5 into 10 grays to the power minus 2 is equal to 45 meter 0 .23 meter per second...