00:01
So in this problem, we have two particles.
00:02
One of them is rotating and the other one is attached to a string being held by the centripetal force of the first one.
00:11
And we want to know what is the string tension and the period of circular motion in the situation where the second particle is stationary.
00:19
So in this problem, we just need to apply neutral second log for each particles and then find the tension and from the tension find the period.
00:28
So we have here that for the first particle, the net force will be equal to the acceleration, the centripetal acceleration, and the net force is equal to the tension.
00:41
And this is m1a1, and the centripetal acceleration is m1b squared over r.
00:50
So we have an expression for tension in terms of m1 v square and r.
00:53
For m2, we have that the net force will be zero, but this is tension minus the weight of the second particle.
01:03
So we have this is equal to zero.
01:06
So this gives us tension equals m2g...