The area of an ellipse is given by $\pi ab$, where $a$ is the semi-major axis and $b$ is the semi-minor axis.
In this case, $a = \frac{V_2 - V_1}{2}$ and $b = \frac{2P_1 - P_2}{2}$.
So, the net work done $W_{net} = \pi ab = \pi \left(\frac{V_2 - V_1}{2}\right)
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