00:02
So in this problem we have this truncated cone and the radius at the bottom is the r1, so r2, yeah.
00:20
And the radius on the top is r1.
00:26
And we also know the height is h.
00:29
So we want to find out the resistance of this wire.
00:35
So basically we just need to look at a very thin sheet on this wire, okay? and the thickness of the sheet is dl, let's say.
00:48
So basically, the resistance of the thin sheet, we have expression d r equal row times dl over the cross section a, right? so the cross section has expression pi times r squared, where r is the radius of the disk.
01:09
And so total resistance equal integral d r.
01:15
Or we can see that this equal integral, row, d l, pi, r squared, right? and in this expression, the l just ranges from 0 to h.
01:30
And before we do this integral, we need to find the relation between l and r.
01:34
So as you can see that, so this is the wire, and this is r2, this is r1, and this is h.
01:48
So actually you can see that this is r...