Question
A mathematics exam consists of 10 multiple-choice questions and 5 open-ended problems in which all work must be shown. If an examinee must answer 8 of the multiple-choice questions and 3 of the open-ended problems, in how many ways can the questions and problems be chosen?
Step 1
The number of ways to choose 8 questions from 10 is given by the combination formula $\binom{n}{r} = \frac{n!}{r!(n-r)!}$, where $n$ is the total number of items, $r$ is the number of items to choose, and $!$ denotes factorial. So, the number of ways to choose the Show more…
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