Question
A metal ion $\mathrm{M}^{\text {at }}$ has a single electron. The highest energy line in its emission spectrum has a frequency of $2.961 \times 10^{16} \mathrm{~Hz}$ Identify the ion.
Step 1
The equation is given by: \[E = \frac{Z^2 \times 2.18 \times 10^{-18}}{n^2}\] where \(E\) is the energy, \(Z\) is the atomic number, and \(n\) is the principal quantum number. Show more…
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