00:01
All right, the problem 130 is to find the formula of the salt.
00:06
So first we know the boiling point of water is equal to 100 celsius degree.
00:15
And the boiling point of the solution, it's 374 .38 kelvin.
00:27
So if we want to convert this into celsius degree minus 273 .15.
00:34
So we get this equal to 101 .23 celsius degree.
00:41
So now we can calculate delta tb is the elevation and boiling point equal to 101 .23 minus 100.
00:54
That's equal to 1 .23 celsius degree.
00:58
And delta tb is also equal to kb times m or kb is the elevation boiling point constant of water.
01:13
So that's delta tb equal to 1 .23, and kb for water is 0 .512 celsius degree per molar, times m is the molality.
01:28
So m is equal to 1 .23 celsius degree divided by 0 .512 celsius per molar, we will get 2 .4 molar.
01:47
So 2 .4 molar is the molality of the solution.
02:03
All right.
02:04
Next step.
02:06
The mass of the sample.
02:08
So we assume the sample mfx.
02:12
So the mass of the sample, we know that's equal to 9 .18 grams.
02:23
And the mass of the solvent is equal to 100 grams.
02:31
The molar mass of the metal m is equal to 96 grams per mole.
02:48
So now we can use the formula of molality equal to number of moles of mfx divided by the mass of water...