0:00
So this is a nice problem.
00:01
I think it's really instructive for relating electric fields to potential.
00:08
So i'm kind of excited to share it.
00:10
So we're given that a sphere has a total charge q of 1 .5 times 10 to the minus 6 kuloms.
00:22
And that's radius is pretty big.
00:25
0 .5 meters.
00:28
And first we want to get the potential at the surface, so that's just going to be kq over r.
00:34
Plugging that into a calculator, i got 27 ,000 volts per meter.
00:42
And then the second question asks us to calculate the distance between the first and second equipotential surface.
00:54
And so the equipotential surfaces are like rings around the sphere, because by symmetry, they're going to all have the same potential.
01:01
So we're going to space the lines out.
01:05
Oh, i wish i had drawn.
01:07
Actually, i'm going to redo this drawing, so i can actually fully do this drawing here with the equipotential lines.
01:13
So i'm going to put this in the middle.
01:16
Okay.
01:18
So here it is.
01:21
And then our equipotential lines all draw in red.
01:28
So as we'll see in the problem, the lines will start off close.
01:36
And then they'll sort of taper off with increasing distance.
01:45
So, okay.
01:47
I mean i should have made my circle smaller.
01:51
So if this distance should probably be a bit bigger.
01:54
Let me go ahead and redraw that.
01:59
Yeah, i definitely should have made this smaller.
02:02
I'm not going to be doing it now, though.
02:05
I'll just try to clean it up a bit.
02:09
So this, yeah, should be like kind of a bigger distance.
02:15
Okay, and so for part a, they want to get the distance between the first and second lines.
02:22
And so at the second line, v is equal to 27 ,000 minus 500, which is 26.
02:31
Oops.
02:38
Oh, i just made a nice discovery...