0:00
Hi there.
00:01
So for this problem, we are told that a metal sphere of radius capital r carries a total charge q, as is shown here in this figure.
00:11
Now, what is the force of repulsion between the northern hemisphere and the southern hemisphere? in here, we have the drawing of the northern hemisphere.
00:26
So we note that inside, it's right in here, inside this, the electric field is equal to zero.
00:38
However, upside, the electric field corresponds to the electric field of a point charge that we know is 1 over 4 times pi times epsilon sub 0 times a charge, capital q divided by the radius square, this in the radial direction.
01:00
So the average electric field is equal to 1 over 2 times 1 over 4 times pi times epsilon sub 0 times the charge capital q divided by the radius capital r to the square, this in the radial direction.
01:24
So if we want to calculate the force per unit length, we're going to call this in the c.
01:31
Direction, that is going to be the charge density, the charge surface density times the average electric field in the c direction.
01:46
Now in this case, we know that the surface charge density is equal to the charge q divided by the surface area that we know is 4 times pi times the radius r to the square.
02:00
So with this, if we want to calculate the force in the cid direction, that is going to be the integral of the force per unit length times the differential in area.
02:13
So we substitute of this expression, so we will have the charge capital q divided by four times pi times the radius r, capital r to the square, this times 1 over 2.
02:27
And this times 1 over 4 times pi xepsilon sub 0 times the charge q divided by the radius capital r to the square.
02:37
And this cosine of theta times the radius capital r square...