00:01
Well, charge of the metallic sphere, q, on the sphere, is equal to 4 nanocolon.
00:12
Nano equals 4 multiplied by 10 to the power minus 9.
00:19
Therefore, charge on sphere equals 4 multiplied by 10 to the power minus 9 cologne.
00:26
And charge on road.
00:29
Charge on road is equal to minus 6 multiply by 10 to the power minus 9 cologne and number of electrons transferred when the road touches the sphere is n and it's equal to 8 .2 multiply by 10 to 9 electrons 9 electrons right so we need to determine the chart the charge is, let's say, q prime on sphere and q prime on road after the road touches the sphere.
01:25
So we need to find out the charge on the sphere and charge on the road after they touch each other.
01:33
So the total charge transferred when the road touches the sphere is equal to the number of electrons transferred multiplied by the charge of each electron.
01:45
So q transferred, let's write down t for q transferred, q transferred equals n times charge on the electron where n is the number of electrons...