00:01
All right, guys, the general form of the reaction can be written like this.
00:05
It's 2 -co2 plus o2.
00:10
And we have the reaction symbol.
00:12
It's a -c -o -2 plus b -c -o plus c -o plus d -o.
00:20
An analysis of the carbon and oxygen gives the following two reactions for the coefficient that is 2 is equal to a plus b.
00:28
This is equation one and then there is three is equal to a plus 0 .5b plus c plus 0 .5d and that is equation 2 so guys moving further the two stoichiometric reactions equivalent for this example and the corresponding equilibrium coefficients are determined from table a 28 for the given temperature so we have co2, the reaction sign co plus 0 .502, natural log kp1 is equal to minus 1 .894.
01:24
And then 02, we have the reaction sign here.
01:30
20 natural log kp2 is equal to minus 5 .826.
01:38
Now, guys, moving further, the equilibrium coefficient relations for these two reactions give the following two equations for the coefficients.
01:48
That is, e raised to power minus 1894, is equal to 2b under root c divided by a under root a plus b plus c plus d...