0:00
Hi everybody.
00:01
So we find the necessary heat transfer and work involved using values from the table.
00:07
So first thing first, it's changed in state 1 and 2.
00:13
The process is polytropic process.
00:16
So we need to find the r mix, which is equal to 0 .5 times 34 .10 plus 0 .5 times 85.
00:31
Point seven six okay and here we get 60 .43 and we needed an b t u so we're going to convert to 0 .07767677 b t u i i mean i wrote that weird i b m r okay and c .p.
01:06
Mix is equal to 0 .5 times 0 .21 plus 0 .5 times 0 .447 equals 0 .3 to 4242 .0 .3 to 4 btu per ibmr.
01:40
Okay.
01:43
And since the process of polytropic, poly, yeah, polytropic, we have p1 over p2 and n minus 1 in equals p1 over 22.
01:58
And we need to take the log of both signs, so log, log.
02:05
So we have n minus 1 over a.
02:10
Log of p1 p2 log of t1 over t2 we need to find n here okay so we've got n minus 1 over a equals oh oops log um which is going to be 150 over 300 equals log equals log of um 280 over 300 equals log of um 280 0 over 900 and so we got 9 minus 1 over n times 1 .69 equals 1 .1349 and now what we're going to do is just solve for n so we've got n equals 3 .397 and um we're going to do is just solve for n so we've got n equals 3 .39937...