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A mixture of calcium carbonate $\left(\mathrm{CaCO}_{3}\right)$ and magnesium carbonate (MgCO $_{3}$ ) of mass 6.26 g reacts completely with hydrochloric acid (HCl) to generate $1.73 \mathrm{L}$ of $\mathrm{CO}_{2}$ at $48^{\circ} \mathrm{C}$ and 1.12 atm. Calculate the mass percentages of $\mathrm{CaCO}_{3}$ and $\mathrm{MgCO}_{3}$ in the mixture.

$$\begin{array}{l}\mathrm{CaCO}_{3}=6.18 \% \\\mathrm{MgCO}_{3}=93.8 \%\end{array}$$

Chemistry 101

Chapter 5

Gases

Rice University

Drexel University

University of Kentucky

Lectures

05:03

In physics, a gas is one of the three major states of matter (the others being liquid and solid). A gas is a fluid that does not support tensile stress, meaning that it is compressible. The word gas is a neologism first used by the early 17th-century Flemish chemist J.B. van Helmont, based on the Greek word ("chaos"), the simplest of all the elemental forms of matter.

04:46

In physics, thermodynamics is the science of energy and its transformations. The three laws of thermodynamics state that energy can be exchanged between physical systems as heat and work; that the total energy of a system can be calculated by adding up all forms of energy in the system; that energy spontaneously flows from being localized to becoming dispersed, spread out, or uniform; and that the entropy of an isolated system not in equilibrium will tend to increase over time, approaching a maximum value at equilibrium.

02:52

A mixture contained calciu…

02:38

02:30

Calcium carbonate reacts w…

06:34

A 6.53 -g sample of a mixt…

10:47

02:44

Dissolving $3.00 \mathrm{g…

I'M given information, we have a mixture of we have a mixture of calcium carbonate and magnesium carbonate, magnesium carbonate of mass 6.26 gram. This reacts reacts completely completely with ice to produce, with a c l to produce 1.73 liter a c o 2848 degrees centigrade and 1.12 pressure find the mass find the mass percentage percentages of calcium carbonate and magnesium carbonate in the mikistereso calculation find the number of moles Of number of moles of c o 2 produced produced a by using general guess equation. T v is equal to n r. T n is equal to p v out of r t. So here we have by putting values. N is equal to 1.12 a t m into 1.73 liter divided by 0.0821 liter. A t m divide by mole per kelvin per mole into we have 48 plus 273 kelvin is equal to 0.0735 mole. Let'S x, be the x b d, mass of mass of calcium carbonate and y b and y b d, the mass of magnesium carbonate. Since the mass of the mixture, the mixture is, is 6.26 gram we can write, it is x, plus y is equal to 6.26. The reaction, the reaction with a l, a t l, shall proceed shall proceed as follows as follows: so we have a reaction c, a c o 3 solid state plus 2, a c l, ducts are c a c l, 2, a form plus c 02 gaseous state Plus h, 2 o in liquid form, so next equation is m g c, o 3 solid state plus 28 l, pickand g c, l, 2 plus c. O 2 in this state, plus h, 2 o in liquid state, find the number of find the number of number of moles of c o 2 moles of c o 2. That can be that can be produced produced from each from each. So we have here x, c, a c o 3 into 1 mole c, a c o 3 divided by 100.08 gram, calcium carbonate into 1 mole of c o 2 divided by 1 mole of c a c o 3 is equal to 9.99 multiply 10 raised to The power minus 3 x and y in gram, magnesium carbonate into 1 mole magnesium carbonate divided by 8431 gram, magnesium carbonate, 1 mole, co, 2, divided by 1. Mole of magnesium carbonate is equal to 0.0119 multiply 10119119 yaso. The sum the sum of number of moles moles of c o 2 from each component, a component must be equal to p equal to 0.0735 mole as calculated as calculated from ideal from ideal gas equation equation. So 9.992 multiply 10 raised to the power minus 3 x, plus 0.01186 y is equal to 0.07352, so 9.992 multiply 10 raised to the power minus 3 x plus 0.0. Double 186 into 6.26 minus x is equal to 0.07352, so x is equal to 0.387 y. Is equal to 6.26 minus x is equal to 6.26. Minus 0.387 is equal to 5.873 grathe. Mass percentage percentage can then can then be obtained obtained as percent c. A c o 3 is equal to 0.387. Divided by 6.26 is equal to 6.18 percent percentage m g c, o 3 magnesium carbonate is equal to 5.873. Divided by 6.26 is equal to 93.8 percent magnesium carbonate.

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