216 \, \mathrm{g} \cdot \mathrm{L}^{-1}$. This means that $0.216 \, \mathrm{g}$ of the gas is present in $1 \, \mathrm{L}$ of the mixture. We can convert this to $1 \, \mathrm{m}^3$ for convenience, so we have $216 \, \mathrm{g}$ of the gas in $1 \, \mathrm{m}^3$
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