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Problem 104

A mixture containing $\mathrm{KClO}_{3}, \mathrm{…


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Problem 103

A mixture of $\mathrm{N}_{2}(g)$ and $\mathrm{H}_{2}(g)$ reacts in a closed container to form ammonia, $\mathrm{NH}_{3}(g) .$ The reaction ceases before either reactant has been totally consumed. At this stage $3.0 \mathrm{mol} \mathrm{N}_{2}, 3.0 \mathrm{mol} \mathrm{H}_{2},$ and 3.0 $\mathrm{mol} \mathrm{NH}_{3}$ are present. How many moles of $\mathrm{N}_{2}$ and $\mathrm{H}_{2}$ were present originally?


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Video Transcript

the gases, nitrogen and hydrogen reacts to form ammonia. Here is the representation and two plus three years to give this to win Itch three. The reaction stops before the total consumption off, either off the reactant where the moves off gas is present are three more off industry. Three more off nitrogen, three moles off hydrogen. This three moves off industry is formed from nitrogen and do on dhe hydrogen. It's too from the balance. Chemically creation. It is seen that one mole off my Trojan on three more off hydrogen produces two. Mole produces two moles off ammonia, then to produce a total of three moles off ammonia required. 1.5 moles off end, too. Blast 4.5 Moles off edge to toe have three moles off in his three, so the number off moles off end to an edge to required each. Originally present in the container is the malls required for forming in its tree. Last moles left after the end off reaction. So if 1.5 morals oh into plus three moles off end too. 4.5 moles off into on DDE 4.5 Moles off. It's too last three moles off EJ two equals 7.5 moles offense, too

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