Question
A mixture of $X \mathrm{Cl}_{3}$ and $\mathrm{XCl}_{5}(\text { see Problem } 3.141)$ weighing 10.00 $\mathrm{g}$ contains 81.04$\% \mathrm{Cl}$ by mass. How many grams of $\mathrm{XCl}_{3}$ and how many grams of $\mathrm{XCl}_{5}$ are present in the mixture?
Step 1
Step 1: Let's denote the mass of $XCl_{3}$ as $x$ and the mass of $XCl_{5}$ as $10 - x$ (since the total mass of the mixture is 10g). Show more…
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A mixture of $\mathrm{XCl}_{3}$ and $\mathrm{XCl}_{5}$ weighing $10.00 \mathrm{~g}$ contains $81.04 \% \mathrm{Cl}$ by mass. How many grams of $\mathrm{XCl}_{3}$ and how many grams of $\mathrm{XCl}_{5}$ are present in the mixture?
Mass Relationships in Chemical Reactions
Determining Molecular Weights: Mass Spectrometry
Element $X$, a member of group 5 A, forms two chlorides, $\mathrm{XCl}_{3}$ and $\mathrm{XCl}_{5} .$ Reaction of an excess of $\mathrm{Cl}_{2}$ with $8.729 \mathrm{~g}$ of $\mathrm{XCl}_{3}$ yields $13.233 \mathrm{~g}$ of $\mathrm{XCl}_{5} .$ What is the atomic weight and the identity of the element X?
Element X forms both a dichloride $\left(\mathrm{XCl}_{2}\right)$ and a tetrachloride $\left(\mathrm{XCl}_{4}\right) .$ Treatment of $10.00 \mathrm{g}$ of $\mathrm{XCl}_{2}$ with excess chlorine forms $12.55 \mathrm{g}$ of $\mathrm{XCl}_{4} .$ Calculate the atomic weight (mass) of $\mathrm{X}$ and identify $\mathrm{X}$.
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