Question
A molecule in n gas moves equal distances $l$ between collisions with equal probability in any direction. After a total of $N$ such disptacements, what is the mean square displacement $\overline{R^{2}}$ of the molecule from its starting point?
Step 1
After the first displacement, the molecule has moved a distance $l$ from its starting point. The mean square displacement at this point is just $l^2$. Show more…
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A molecule in a gas moves equal distances l between collisions with equal probability in any direction. After a total of n such displacements, what is the mean square displacement r2 of the molecule from its starting point
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In a sample of ideal gas the probability that a gas molecule will travel a distance between r1 and r2 before colliding with another molecule is given by P(r1;r2) = ∫_{r1}^{r2} Ae^{-cr} dr where A and c are constant parameters to be determined. Note, ∫_{0}^{∞} r^{n}e^{-cr} dr = n!/c^{n+1}. (a) The probability that a gas molecule will travel between r = 0 and r → ∞ is one hundred percent, P(0; ∞) = 1. Use this to determine A in terms of c. (b) Compute the average distance traveled before colliding with another molecule, ⟨r⟩. (c) Equate the average distance to the mean free path, ⟨r⟩ = λ, to determine the constant c in terms of λ. (d) Rewrite P(r1;r2) using the mean free path λ as the only parameter.
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