Question
A motor run by a 9.0-V battery has a 20-turn square coil with sides of length 5.0 cm and total resistance 28 $\Omega$. When spinning, the magnetic field felt by the wire in the coil is 0.020 T. What is the maximum torque on the motor?
Step 1
We can use Ohm's law for this, which states that the current is equal to the voltage divided by the resistance. In mathematical terms, this is written as $I = \frac{V}{R}$. Show more…
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A motor run by a $9.0-\mathrm{V}$ battery has a 20 turn square coil with sides of length 5.0 $\mathrm{cm}$ and total resistance 24$\Omega .$ When spinning, the magnetic field felt by the wire in the coil is 0.020 $\mathrm{T} .$ What is the maximum torque on the motor?
In an electric motor, a coil with 100 turns of radius $2.0 \mathrm{cm}$ can rotate between the poles of a magnet. The magnetic field strength is $0.20 \mathrm{T}$. When the current through the coil is $50.0 \mathrm{mA},$ what is the maximum torque that the motor can deliver?
In an electric motor, a coil with 100 turns of radius $2.0 \mathrm{cm}$ can rotate between the poles of a magnet. The magnetic field magnitude is $0.20 \mathrm{T}$. When the current through the coil is $50.0 \mathrm{mA},$ what is the maximum torque that the motor can deliver?
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