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A motorcycle moves according to the velocity-versus-timegraph shown in FloukE $2-35 .$ Find the average acceleration of themotorcycle during each of the following segments of the motion:(a) $\mathrm{A},$ (b) $\mathrm{B},$ and (c) $\mathrm{C}$ .

(a) 2$m / s^{2}$(b) 0 $\mathrm{m} / \mathrm{s}^{2}$(c) $-0.5 \mathrm{m} / \mathrm{s}^{2}$

Physics 101 Mechanics

Chapter 2

One-Dimensional Kinematics

Motion Along a Straight Line

Cornell University

Simon Fraser University

University of Sheffield

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So in this question, we need to find the average acceleration off a mortal cycle in each segment off a graph. Well, the only thing we need to know is weak in the reeds. We can write the average acceleration as a difference in velocity divided by the difference in time. So if we look to the the graph, we can see that first segment segment A we go from velocity zero velocity 10 in just five seconds. So the average acceleration in the first segment is just going to be 10 miners ear divided by five. This is going to be acceleration, of course. True. Two meters per second squared. This is the average acceleration. The first segment, the second segment segments be We stay in the same velocity we skip in 10 meters per second. We don't change your velocity. So if we don't change your velocity, that means we don't have acceleration. So the acceleration in this segment be It's just a deer years per second. Scratch. Okay, so their final segments segment see? Let's see what we have. We go from the lost city 10 to velocity five in how much time? In 10 seconds. 10 seconds. So using their creation, we know that average acceleration of the final segment is just five miners, 10 divided by done. Always remember that difference is just final minors in you. Sure. So this is going to be a minus five divided by this is just miners 0.5 meters per second squared. So in this segment, the motorcycle is decelerating. Well, that's the final answer. Thanks for watching.

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