00:01
For this problem, we're told that there's a lake that holds some water that's initially at some temperature and that some ice from an iceberg ends up floating in the lake.
00:17
And we want to assume that no energy exchanges except between the lake water and the ice and to determine what's the final temperature and how much if any ice remains.
00:29
So i thought that the best way to approach this is to sort of go in steps.
00:36
So first, i want to write down all of the information and make sure it is organized.
00:42
So i'm going to specifically do this using two different colors.
00:46
So we'll make the lake red.
00:50
And so we're told the volume of the lake.
00:53
The volume of the lake is 185 ,000 cubic meters.
01:00
We're also told the initial temperature of the lake, it is 6 .4 degrees celsius.
01:11
Thinking about this problem, we're probably going to need to use the equation, q is equal to mc delta t, or q is equal to ml.
01:27
And so i immediately want to figure out what the mass of water in the lake is.
01:33
Because we'll probably need to use that.
01:37
So mass is generally given as density times volume.
01:44
We know the volume of the lake and the lake is filled with water.
01:48
So we can just multiply by the density of water, which is 1 ,000 kilograms per cubic meter.
01:58
So multiplying by 1 ,000, we get that the mass of the water is 1 .85.
02:03
Times 10 to the 8 kilograms.
02:10
For the iceberg, we'll make it blue.
02:17
The iceberg, we're told, has a mass m sub i of 17 .3 times 10 to the 6 kilograms, and an initial temperature t sub i of negative 10 degrees celsius.
02:37
Some additional pieces of information that will probably be useful, again, assuming that we'll have to use one of those two equations that i gave up there, is the specific heat of water, which is 4 .184 times 10 to the third joules per kilogram kelvin, as well as the specific heat for ice, which is 4 .184 times 10 to the third, joules per kilogram kelvin, 2 .093 times 10 to the third joules per kilogram kelvin.
03:18
And lastly, the latent heat of fusion for water, which is 334 kilojoules per kilogram.
03:31
So my first thought was there are a few things that can't happen.
03:38
We firstly need to be able to cool the water to zero degrees celsius.
03:48
So how much energy is needed to cool the water to zero degrees celsius? so q to cool the water is going to be mc delta t.
04:09
And in this case, we're considering the lake.
04:13
So this will be the mass of the lake times the specific heat of water.
04:18
Times the change in temperature.
04:20
It starts at 6 .4 degrees celsius and ends at 0 degrees celsius.
04:26
So delta t is going to be 6 .4.
04:33
And so when you plug all of that end, you get that we need 4 .954 times 10 to the 12 joules of energy to cool the water to zero degrees celsius.
04:49
Now it's a matter of figuring out if that actually happens.
04:55
So the first thing once the ice hit the water is that the ice also needs to reach zero degrees celsius.
05:03
So next i want to figure out how much energy is needed to warm the ice to zero degrees celsius.
05:13
And so we're going to use that same equation...