Question
A narrow beam of light with wavelengths from 450 nm to $700 \mathrm{nm}$ is incident perpendicular to one face of a prism made of crown glass, for which the index of refraction ranges from $n=1.533$ to $n=1.517$ for those wavelengths. The light strikes the opposite side of the prism at an angle of $40^{\circ} .$ What is the angular spread of the beam as it leaves the prism?
Step 1
So, we can write this as: \[n_1 \sin(\theta_1) = n_2 \sin(\theta_2)\] where \(n_1\) and \(n_2\) are the indices of refraction for the two media, and \(\theta_1\) and \(\theta_2\) are the angles of incidence and refraction, respectively. Show more…
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A narrow beam of light with wavelengths from $450 \mathrm{nm}$ to $700 \mathrm{nm}$ is incident perpendicular to one face of a $40.00^{\circ}$ prism made of crown glass, for which the index of refraction ranges from $n=1.533$ to $n=1.517$ for those wavelengths. What is the angular spread of the beam after passing through the prism?
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