Question

A narrow tube is sealed onto a tank as shown in Fig. $13-8 .$ The base of the tank has an area of $80 \mathrm{~cm}^{2}$. (a) Remembering that pressure is determined by the height of the column of liquid, find the force on the bottom of the tank due to oil when the tank and capillary are filled with oil $\left(\rho=0.72 \mathrm{~g} / \mathrm{cm}^{3}\right)$ to the height $\mathrm{h}_{1}$. ( $b$ ) Repeat for an oil height of $\mathrm{h}_{2}$.

Name: Problem 35, Chapter 13: Schaum’s Outline of College Physics
Uploaded: 2022-02-27T05:04:36-08:00
Duration: 3 min 56 s
Channel: Arpit Gupta
Description: A narrow tube is sealed onto a tank as shown in Fig. 13-8 . The base of the tank has an area of 80 cm^2. (a) Remembering that pressure is determined by the height of the column of liquid, find the force on the bottom of the tank due to oil when the tank and capillary are filled with oil (ρ=0.72 g / cm^3) to the height h1. ( b ) Repeat for an oil height of h2.

   A narrow tube is sealed onto a tank as shown in Fig. $13-8 .$ The base of the tank has an area of $80 \mathrm{~cm}^{2}$.
(a) Remembering that pressure is determined by the height of the column of liquid, find the force on the bottom of the tank due to oil when the tank and capillary are filled with oil $\left(\rho=0.72 \mathrm{~g} / \mathrm{cm}^{3}\right)$ to the height $\mathrm{h}_{1}$. ( $b$ ) Repeat for an oil height of $\mathrm{h}_{2}$.

Schaum’s Outline of College Physics

Eugene Hecht 12th Edition

Chapter 13, Problem 35

Instant Answer

Solved by Expert Arpit Gupta

02/27/2022

Step 1

The pressure is given by the formula: P = ρgh where P is the pressure, ρ is the density of the oil (0.72 g/cm³), g is the acceleration due to gravity (approximately 980 cm/s²), and h is the height of the oil column (h1). Now, we can plug in the values: P = Show more…

Show all steps

Thanks for your feedback!

A narrow tube is sealed onto a tank as shown in Fig. $13-8 .$ The base of the tank has an area of $80 \mathrm{~cm}^{2}$. (a) Remembering that pressure is determined by the height of the column of liquid, find the force on the bottom of the tank due to oil when the tank and capillary are filled with oil $\left(\rho=0.72 \mathrm{~g} / \mathrm{cm}^{3}\right)$ to the height $\mathrm{h}_{1}$. ( $b$ ) Repeat for an oil height of $\mathrm{h}_{2}$.

Play audio

Feedback

Arpit Gupta and 100 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Force due to Pressure on a Surface

The force exerted by a fluid on a surface is determined by multiplying the pressure acting on the surface by the area of that surface. This relationship is expressed as F = pA, where F is the force, p is the pressure, and A is the area. This concept allows for the calculation of the net force on any boundary in contact with a fluid, which is essential in fluid mechanics and related engineering applications.

Hydrostatic Pressure

Hydrostatic pressure is the pressure exerted by a fluid at rest due to the gravitational force acting on it. It is directly proportional to the depth of the fluid column and is calculated using the equation p = ?gh, where ? is the fluid density, g is the acceleration due to gravity, and h is the height of the fluid above the point of measurement. This concept is fundamental in understanding how pressure varies within fluids at rest.

Please give Ace some feedback