00:04
So for this problem, we have a sheet of glass, and we have a light beam that is white light incident upon it at an angle of theta 1.
00:18
Now, white light is composed of different colors of light.
00:22
So for our purposes, we're going to state that one of these beams is reflected at an angle theta 3 and the other at theta 2, because they have different wavelengths and therefore different refractive indexes.
00:38
So now we have our setup.
00:41
We're going to say that at 400 nanometers, which we're going to say is the lower end of the spectrum of the white light, the refractive index is going to be 1 .47.
00:55
So n1, sine theta 1 is equal to n2 sine theta 2.
01:01
We're going to plug in our values because we know that the angle of incidence is 30 degrees.
01:06
So we want to say that sine of 30 is equal to n2, which is 1 .47, sine of theta 2...