Question
A nearsighted patient's far point is $0.690 \mathrm{~m}$ from her eyes. She is able to see distant objects in focus when wearing glasses with a refractive power of $-1.50$ diopters. What is the distance between her eyes and the glasses?
Step 1
So, we have $P = -1.50$ diopters, which implies $f = \frac{1}{P} = -\frac{1}{1.50} = -0.67$ m. Show more…
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A nearsighted patient's far point is $0.690 \mathrm{~m}$ from her eyes. She is able to see distant objects in focus when wearing glasses with a refractive power of -1.50 diopters. What is the distance between her eyes and the glasses?
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