0:00
Hello everyone.
00:01
In this problem we're going to be investigating the electric fields of neurons and how far they can be sensed by certain species of sharks.
00:11
So first we're told that we are we that you know scientists have measured that roughly when an electric signal is transmitted through the neurons you have about 5 .6 10 10 .11 potassium or atrium plus ions per meter and entering the nora.
00:32
So this tells you what is the density of this types of ions, and then, sorry, sodium, sodium density in the entering the ion.
00:45
And then in order to find or convert this to a church density, we can just multiply by the charge of the sodium ions, which is just one e, but positive.
00:55
So this were set to be 5 .6 times 10 to 11 times 1 .6 times 10 to e minus 19.
01:00
Or 8 .96 times the minus 8 coulum meters.
01:05
So this is the charge density of the neurons if the charges were distributed uniformly throughout the entire neuron.
01:15
And so the question is, or part one of the question is, how much of this charge or how much charge can be found given that we model the neuron as a long tube in a given length of the tube, which is 0 .1 0mm millimeters or 1 times 10 to minus 4 meters.
01:35
So all we have to do here is just realize that now we have a charge density, which is like a linear charge density, and we have a length.
01:44
So we just have to multiply those together to get the charge out.
01:48
Because the linear chart density, remember, is just charge over length.
01:52
So dimensionally, you know, this would be what you would naively do in any way, even if you didn't know what the charge density meant.
02:00
Because you looked at it and you would see that you have charge over length.
02:04
So you would have to look by a length to get at the charge.
02:08
So that's kind of what i'm trying to show you here with this little approximation of what's going on.
02:14
So we have the neuron.
02:15
It's got a long tube.
02:16
There are charges all the way through it.
02:18
And assuming they're roughly uniformly distributed, we can then approximate this little length of 0 .1 millimeters as a point.
02:27
Charge of q.
02:30
And so q you can find by multiplying the charge density with length and that works out to be 8 .96 times 10 to minus 12 kuloms...