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A net external force is applied to a $6.00-\mathrm{kg}$ object that is initially at rest. The net force component along the displacement of the object varies with the magnitude of the displacement as shown in the drawing. What is the speed of the object at $s=20.0 \mathrm{~m} ?$

7.07 $\mathrm{m.s}^{-1}$

Physics 101 Mechanics

Chapter 6

Work and Energy

Work

Kinetic Energy

Cornell University

Rutgers, The State University of New Jersey

Simon Fraser University

Lectures

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

02:08

In physics, work is the transfer of energy by a force acting through a distance. The "work" of a force F on an object that it pushes is defined as the product of the force and the distance through which it moves the object. For example, if a force of 10 newtons (N) acts through a distance of 2 meters (m), then doing 10 joules (J) of work on that object requires exerting a force of 10 N for 2 m. Work is a scalar quantity, meaning that it can be described by a single number-for example, if a force of 3 newtons acts through a distance of 2 meters, then the work done is 6 joules. Work is due to a force acting on a point that is stationary-that is, a point where the force is applied does not move. By Newton's third law, the force of the reaction is equal and opposite to the force of the action, so the point where the force is applied does work on the person applying the force. In the example above, the force of the person pushing the block is 3 N. The force of the block on the person is also 3 N. The difference between the two forces is the work done on the block by the person, which can be calculated as the force of the block times the distance through which it moves, or 3 N × 2 m = 6 J.

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A net external force is ap…

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CALC A net force along the…

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Starting at $t=0$ a net ex…

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At $t=0$, force $\vec{F}=(…

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A $3.00-\mathrm{kg}$ objec…

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01:28

At $t=0,$ force $\vec{F}=(…

Okay, You take a look at the graph. The work down actually equal to the area off the rack, which is a plus B over to that age. Okay, so this is the formula for the area of the trapezoid, since the shape of a graph is a trapper Soy Okay, ace. The upper bass beats the lower base and Asia's the heights. So we know the upper bases. 10 meter and lower. Basic legal, 20 meter in the highest. All the troubles, always 10 Newtons. So therefore, that's determined. Work down so they weren't down. Should be equal to 10.0 meter plus 20.0 meter over to and sometimes tempo Newton, which is equal to 1 50 Que. And we know the work down in this case can be able to the change in kinetic energy to say del Okay, which is, uh, 1/2 I m finals be square minus, uh, initials V Square. Okay, so since initially it was arrested, Miss FBI School zero. So therefore, we have, uh, you work down is Justin political Teoh Donna K, which is equal to while half MV finals. Where? Okay, so therefore we final square. You're able to two times work down over the mass of the objects. And we know the mass off objects was given 6.0 kilograms, which will give us the final SBI Square should be equal to two times 1 50 que over 6.8 kilograms. So therefore, if I know speedy another word this fee off object a ask you 20.0 meter should be equal to the square rule two times. I want to teach you over 6.8 kilograms and this is equal to seven point 07 meter per second. Okay, and this is the answer. His question.

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