A neutral water molecule (H2 O) in its vapour state has an electric dipole moment of 6 ×10^-30 C

Name: Problem 38, Chapter 17: Master Resource Book in JEE Main Physics
Uploaded: 2022-01-30T08:13:39-08:00
Duration: 1 min 19 s
Channel: Yuva S
Description: A neutral water molecule (H2 O) in its vapour state has an electric dipole moment of 6 ×10^-30 Cm. If the molecule is placed in an electric field of 1.5 ×10^4 NC^-1, the maximum torque that the field can exert on it is nearly (a) 4.5 ×10^-26 N-m (b) 4 ×10^-34 N-m (c) 9 ×10^-26 N-m (d) 6 ×10^-26 N-m

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Question

A neutral water molecule $\left(\mathrm{H}_{2} \mathrm{O}\right)$ in its vapour state has an electric dipole moment of $6 \times 10^{-30} \mathrm{Cm}$. If the molecule is placed in an electric field of $1.5 \times 10^{4} \mathrm{NC}^{-1}$, the maximum torque that the field can exert on it is nearly (a) $4.5 \times 10^{-26} \mathrm{~N}-\mathrm{m}$ (b) $4 \times 10^{-34} \mathrm{~N}-\mathrm{m}$ (c) $9 \times 10^{-26} \mathrm{~N}-\mathrm{m}$ (d) $6 \times 10^{-26} \mathrm{~N}-\mathrm{m}$

   A neutral water molecule $\left(\mathrm{H}_{2} \mathrm{O}\right)$ in its vapour state has an electric dipole moment of $6 \times 10^{-30} \mathrm{Cm}$. If the molecule is placed in an electric field of $1.5 \times 10^{4} \mathrm{NC}^{-1}$, the maximum torque that the field can exert on it is nearly
(a) $4.5 \times 10^{-26} \mathrm{~N}-\mathrm{m}$
(b) $4 \times 10^{-34} \mathrm{~N}-\mathrm{m}$
(c) $9 \times 10^{-26} \mathrm{~N}-\mathrm{m}$
(d) $6 \times 10^{-26} \mathrm{~N}-\mathrm{m}$

Master Resource Book in JEE Main Physics

D. B. Singh 1st Edition

Chapter 17, Problem 38

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Solved by Expert Yuva S

01/30/2022

Step 1

Step 1: The torque on a dipole in an electric field is given by the formula $\tau = pE\sin\theta$, where $p$ is the dipole moment, $E$ is the electric field, and $\theta$ is the angle between the dipole moment and the electric field. Show more…

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A neutral water molecule $\left(\mathrm{H}_{2} \mathrm{O}\right)$ in its vapour state has an electric dipole moment of $6 \times 10^{-30} \mathrm{Cm}$. If the molecule is placed in an electric field of $1.5 \times 10^{4} \mathrm{NC}^{-1}$, the maximum torque that the field can exert on it is nearly (a) $4.5 \times 10^{-26} \mathrm{~N}-\mathrm{m}$ (b) $4 \times 10^{-34} \mathrm{~N}-\mathrm{m}$ (c) $9 \times 10^{-26} \mathrm{~N}-\mathrm{m}$ (d) $6 \times 10^{-26} \mathrm{~N}-\mathrm{m}$

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Key Concepts

Electric Dipole Moment

Electric dipole moment is a measure of the separation of positive and negative charges within a molecule. It is a vector quantity, and its magnitude and direction determine how the molecule interacts with external electric fields.

Electric Field

An electric field is a region of space where an electric charge experiences a force. It is defined as the force per unit charge and is fundamental to understanding how charges, including those within dipoles, interact with their surroundings.

Torque on a Dipole

Torque on a dipole in an electric field arises from the tendency of the dipole to align itself with the field. The torque is given by the cross product of the dipole moment and the electric field, reaching its maximum value when the dipole is oriented perpendicular to the field.

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