Question
A neutron moving with velocity $\mathrm{v}_{\mathrm{n}}$ has an inelastic collision with a stationary singly ionized helium ion and both are deflected at $45^{\circ}$ to the original path of the neutron. The helium ion gives out a radiation of $48.36 \mathrm{eV}$ and comes to the ground state. If $\mathrm{v}_{\mathrm{n}}$ ' and $\mathrm{v}_{\mathrm{H}}$ are the final velocities of neutron and helium,(a) $\mathrm{v}_{\mathrm{n}}=\sqrt{2} \mathrm{v}_{\mathrm{n}}$(b) $\mathrm{v}_{\mathrm{H}}=\frac{\mathrm{v}_{\mathrm{n}}}{4}$(c) $\mathrm{v}_{\mathrm{H}}=\frac{\mathrm{v}_{\mathrm{n}}}{4 \sqrt{2}}$(d) If the excited electron gives out more than one radiation instead of a single radiation, the largest possible wavelength is $1643 \AA$.
Step 1
6$ eV, where $Z$ is the atomic number and $n$ is the principal quantum number. For helium, $Z = 2$, so the energy levels are $E = -\frac{4}{n^2} \times 13.6$ eV, or $E = -\frac{54.4}{n^2}$ eV. Show more…
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